Base | Representation |
---|---|
bin | 11001010111111100… |
… | …01011111110000011 |
3 | 1022011101101000012111 |
4 | 30223332023332003 |
5 | 210344342433011 |
6 | 10131432040151 |
7 | 661403252224 |
oct | 145376137603 |
9 | 38141330174 |
10 | 13622624131 |
11 | 5860686156 |
12 | 2782233057 |
13 | 139138c24c |
14 | 93332124b |
15 | 54ae3d121 |
hex | 32bf8bf83 |
13622624131 has 2 divisors, whose sum is σ = 13622624132. Its totient is φ = 13622624130.
The previous prime is 13622624101. The next prime is 13622624137. The reversal of 13622624131 is 13142622631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13622624131 - 213 = 13622615939 is a prime.
It is a super-2 number, since 2×136226241312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13622624093 and 13622624102.
It is not a weakly prime, because it can be changed into another prime (13622624137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6811312065 + 6811312066.
It is an arithmetic number, because the mean of its divisors is an integer number (6811312066).
Almost surely, 213622624131 is an apocalyptic number.
13622624131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13622624131 is an equidigital number, since it uses as much as digits as its factorization.
13622624131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10368, while the sum is 31.
The spelling of 13622624131 in words is "thirteen billion, six hundred twenty-two million, six hundred twenty-four thousand, one hundred thirty-one".
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