Base | Representation |
---|---|
bin | 1100011001000101001000… |
… | …1100010110011011101010 |
3 | 1210020112112201221001021110 |
4 | 3012101102030112123222 |
5 | 3241213012344412414 |
6 | 44551125014051150 |
7 | 2604242402411550 |
oct | 306212214263352 |
9 | 53215481831243 |
10 | 13625015232234 |
11 | 438337799353a |
12 | 1640752049ab6 |
13 | 77aaab053393 |
14 | 351650699bd0 |
15 | 1896406d5459 |
hex | c64523166ea |
13625015232234 has 64 divisors (see below), whose sum is σ = 31608719041536. Its totient is φ = 3834636816384.
The previous prime is 13625015232211. The next prime is 13625015232277. The reversal of 13625015232234 is 43223251052631.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13625015232192 and 13625015232201.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 123133177 + ... + 123243779.
It is an arithmetic number, because the mean of its divisors is an integer number (493886235024).
Almost surely, 213625015232234 is an apocalyptic number.
13625015232234 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13625015232234 is an abundant number, since it is smaller than the sum of its proper divisors (17983703809302).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13625015232234 is a wasteful number, since it uses less digits than its factorization.
13625015232234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 154459.
The product of its (nonzero) digits is 259200, while the sum is 39.
Adding to 13625015232234 its reverse (43223251052631), we get a palindrome (56848266284865).
The spelling of 13625015232234 in words is "thirteen trillion, six hundred twenty-five billion, fifteen million, two hundred thirty-two thousand, two hundred thirty-four".
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