Base | Representation |
---|---|
bin | 11001011000010000… |
… | …01000010000000101 |
3 | 1022011120021102020210 |
4 | 30230020020100011 |
5 | 210401024332331 |
6 | 10132003550033 |
7 | 661434355422 |
oct | 145410102005 |
9 | 38146242223 |
10 | 13625230341 |
11 | 58620a6248 |
12 | 278308b319 |
13 | 1391a92598 |
14 | 9337dcd49 |
15 | 54b2a5446 |
hex | 32c208405 |
13625230341 has 8 divisors (see below), whose sum is σ = 18793421280. Its totient is φ = 8770263152.
The previous prime is 13625230319. The next prime is 13625230357. The reversal of 13625230341 is 14303252631.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13625230341 - 211 = 13625228293 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13625230299 and 13625230308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13625230141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 78305835 + ... + 78306008.
It is an arithmetic number, because the mean of its divisors is an integer number (2349177660).
Almost surely, 213625230341 is an apocalyptic number.
It is an amenable number.
13625230341 is a deficient number, since it is larger than the sum of its proper divisors (5168190939).
13625230341 is a wasteful number, since it uses less digits than its factorization.
13625230341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 156611875.
The product of its (nonzero) digits is 12960, while the sum is 30.
Adding to 13625230341 its reverse (14303252631), we get a palindrome (27928482972).
The spelling of 13625230341 in words is "thirteen billion, six hundred twenty-five million, two hundred thirty thousand, three hundred forty-one".
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