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13626772462057 is a prime number
BaseRepresentation
bin1100011001001011101011…
…1011101001100111101001
31210020201002012110120102111
43012102322323221213221
53241230112222241212
644552015225402321
72604334060542556
oct306227273514751
953221065416374
1013626772462057
114384099895297
121640b626393a1
1377accb119a41
14351779bdba2d
151896e4ae0ea7
hexc64baee99e9

13626772462057 has 2 divisors, whose sum is σ = 13626772462058. Its totient is φ = 13626772462056.

The previous prime is 13626772462033. The next prime is 13626772462097. The reversal of 13626772462057 is 75026427762631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9603683238361 + 4023089223696 = 3098981^2 + 2005764^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13626772462057 is a prime.

It is a super-3 number, since 3×136267724620573 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13626772461992 and 13626772462010.

It is not a weakly prime, because it can be changed into another prime (13626772462007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6813386231028 + 6813386231029.

It is an arithmetic number, because the mean of its divisors is an integer number (6813386231029).

Almost surely, 213626772462057 is an apocalyptic number.

It is an amenable number.

13626772462057 is a deficient number, since it is larger than the sum of its proper divisors (1).

13626772462057 is an equidigital number, since it uses as much as digits as its factorization.

13626772462057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 35562240, while the sum is 58.

The spelling of 13626772462057 in words is "thirteen trillion, six hundred twenty-six billion, seven hundred seventy-two million, four hundred sixty-two thousand, fifty-seven".