Base | Representation |
---|---|
bin | 111111011110110010… |
… | …0000010101111001101 |
3 | 111000212200021102012220 |
4 | 1332331210002233031 |
5 | 4213143012002042 |
6 | 142343155245553 |
7 | 12564146446365 |
oct | 1767544025715 |
9 | 430780242186 |
10 | 136324328397 |
11 | 528a6590714 |
12 | 225068a98b9 |
13 | cb1720899a |
14 | 68533c19a5 |
15 | 382d1b38ec |
hex | 1fbd902bcd |
136324328397 has 16 divisors (see below), whose sum is σ = 192547837440. Its totient is φ = 85496850432.
The previous prime is 136324328341. The next prime is 136324328447. The reversal of 136324328397 is 793823423631.
It is a happy number.
It is not a de Polignac number, because 136324328397 - 26 = 136324328333 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (136324318397) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 514372 + ... + 732957.
It is an arithmetic number, because the mean of its divisors is an integer number (12034239840).
Almost surely, 2136324328397 is an apocalyptic number.
136324328397 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
136324328397 is a deficient number, since it is larger than the sum of its proper divisors (56223509043).
136324328397 is a wasteful number, since it uses less digits than its factorization.
136324328397 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1249492.
The product of its digits is 3919104, while the sum is 51.
The spelling of 136324328397 in words is "one hundred thirty-six billion, three hundred twenty-four million, three hundred twenty-eight thousand, three hundred ninety-seven".
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