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136336210047 = 341683163087
BaseRepresentation
bin111111011111001000…
…1010111100001111111
3111000220111122001210000
41332332101113201333
54213204032210142
6142344302045343
712564352443642
oct1767621274177
9430814561700
10136336210047
1152902266564
122250a879853
13cb19808b4b
146854bd5a59
15382e25e14c
hex1fbe45787f

136336210047 has 10 divisors (see below), whose sum is σ = 203662733648. Its totient is φ = 90890806644.

The previous prime is 136336210033. The next prime is 136336210079. The reversal of 136336210047 is 740012633631.

136336210047 is a `hidden beast` number, since 1 + 3 + 633 + 6 + 2 + 10 + 0 + 4 + 7 = 666.

It is a de Polignac number, because none of the positive numbers 2k-136336210047 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 136336209993 and 136336210020.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (136336210027) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 841581463 + ... + 841581624.

Almost surely, 2136336210047 is an apocalyptic number.

136336210047 is a deficient number, since it is larger than the sum of its proper divisors (67326523601).

136336210047 is an equidigital number, since it uses as much as digits as its factorization.

136336210047 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1683163099 (or 1683163090 counting only the distinct ones).

The product of its (nonzero) digits is 54432, while the sum is 36.

Adding to 136336210047 its reverse (740012633631), we get a palindrome (876348843678).

The spelling of 136336210047 in words is "one hundred thirty-six billion, three hundred thirty-six million, two hundred ten thousand, forty-seven".

Divisors: 1 3 9 27 81 1683163087 5049489261 15148467783 45445403349 136336210047