Base | Representation |
---|---|
bin | 11111000000011001010000… |
… | …100111010010111011100001 |
3 | 122212211111221022121211211012 |
4 | 133000121100213102323201 |
5 | 120333212210404021213 |
6 | 1202005533522230305 |
7 | 40503105403660004 |
oct | 3700312047227341 |
9 | 585744838554735 |
10 | 136366564126433 |
11 | 3a4a580a420313 |
12 | 133649064b5395 |
13 | 5b124090b4b34 |
14 | 259626967b53b |
15 | 10b731985e4a8 |
hex | 7c06509d2ee1 |
136366564126433 has 2 divisors, whose sum is σ = 136366564126434. Its totient is φ = 136366564126432.
The previous prime is 136366564126417. The next prime is 136366564126469. The reversal of 136366564126433 is 334621465663631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 116044752573649 + 20321811552784 = 10772407^2 + 4507972^2 .
It is a cyclic number.
It is not a de Polignac number, because 136366564126433 - 24 = 136366564126417 is a prime.
It is not a weakly prime, because it can be changed into another prime (136366564126493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68183282063216 + 68183282063217.
It is an arithmetic number, because the mean of its divisors is an integer number (68183282063217).
Almost surely, 2136366564126433 is an apocalyptic number.
It is an amenable number.
136366564126433 is a deficient number, since it is larger than the sum of its proper divisors (1).
136366564126433 is an equidigital number, since it uses as much as digits as its factorization.
136366564126433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 100776960, while the sum is 59.
The spelling of 136366564126433 in words is "one hundred thirty-six trillion, three hundred sixty-six billion, five hundred sixty-four million, one hundred twenty-six thousand, four hundred thirty-three".
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