Base | Representation |
---|---|
bin | 111111100001000010… |
… | …1100010001110000011 |
3 | 111001001222001221202112 |
4 | 1333002011202032003 |
5 | 4213321423420323 |
6 | 142354510005535 |
7 | 12566060500013 |
oct | 1770205421603 |
9 | 431058057675 |
10 | 136400216963 |
11 | 5293540393a |
12 | 225281a68ab |
13 | cb29b5986a |
14 | 685d4d7c43 |
15 | 3834ba4178 |
hex | 1fc2162383 |
136400216963 has 2 divisors, whose sum is σ = 136400216964. Its totient is φ = 136400216962.
The previous prime is 136400216959. The next prime is 136400216989. The reversal of 136400216963 is 369612004631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 136400216963 - 22 = 136400216959 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 136400216963.
It is not a weakly prime, because it can be changed into another prime (136400216863) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68200108481 + 68200108482.
It is an arithmetic number, because the mean of its divisors is an integer number (68200108482).
Almost surely, 2136400216963 is an apocalyptic number.
136400216963 is a deficient number, since it is larger than the sum of its proper divisors (1).
136400216963 is an equidigital number, since it uses as much as digits as its factorization.
136400216963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 41.
The spelling of 136400216963 in words is "one hundred thirty-six billion, four hundred million, two hundred sixteen thousand, nine hundred sixty-three".
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