Base | Representation |
---|---|
bin | 1100011010000001000110… |
… | …1110110000000011111110 |
3 | 1210022002002122211212122001 |
4 | 3012200101232300003332 |
5 | 3241444000040202004 |
6 | 45002350250012514 |
7 | 2605352340316240 |
oct | 306402156600376 |
9 | 53262078755561 |
10 | 13641113600254 |
11 | 438a189005718 |
12 | 16438a541713a |
13 | 77c4752cb32a |
14 | 35233a716090 |
15 | 189c83b5c1a4 |
hex | c6811bb00fe |
13641113600254 has 8 divisors (see below), whose sum is σ = 23384766171888. Its totient is φ = 5846191542960.
The previous prime is 13641113600209. The next prime is 13641113600269. The reversal of 13641113600254 is 45200631114631.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 487182628567 + ... + 487182628594.
It is an arithmetic number, because the mean of its divisors is an integer number (2923095771486).
Almost surely, 213641113600254 is an apocalyptic number.
13641113600254 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13641113600254 is a deficient number, since it is larger than the sum of its proper divisors (9743652571634).
13641113600254 is an equidigital number, since it uses as much as digits as its factorization.
13641113600254 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 974365257170.
The product of its (nonzero) digits is 51840, while the sum is 37.
Adding to 13641113600254 its reverse (45200631114631), we get a palindrome (58841744714885).
The spelling of 13641113600254 in words is "thirteen trillion, six hundred forty-one billion, one hundred thirteen million, six hundred thousand, two hundred fifty-four".
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