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13641113600400 = 243521113296014561
BaseRepresentation
bin1100011010000001000110…
…1110110000000110010000
31210022002002122211212211110
43012200101232300012100
53241444000040203100
645002350250013320
72605352340316536
oct306402156600620
953262078755743
1013641113600400
11438a189005840
1216438a5417240
1377c4752cb410
1435233a716156
15189c83b5c250
hexc6811bb0190

13641113600400 has 960 divisors, whose sum is σ = 53206622058240. Its totient is φ = 2941747200000.

The previous prime is 13641113600347. The next prime is 13641113600419. The reversal of 13641113600400 is 400631114631.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 2990814120 + ... + 2990818680.

It is an arithmetic number, because the mean of its divisors is an integer number (55423564644).

Almost surely, 213641113600400 is an apocalyptic number.

13641113600400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13641113600400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26603311029120).

13641113600400 is an abundant number, since it is smaller than the sum of its proper divisors (39565508457840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13641113600400 is a wasteful number, since it uses less digits than its factorization.

13641113600400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5236 (or 5225 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 30.

The spelling of 13641113600400 in words is "thirteen trillion, six hundred forty-one billion, one hundred thirteen million, six hundred thousand, four hundred".