Base | Representation |
---|---|
bin | 10011110110011101100… |
… | …000110000111110000011 |
3 | 11211102002202201010111111 |
4 | 103312131200300332003 |
5 | 134322233143314211 |
6 | 2522403001424151 |
7 | 200361561156232 |
oct | 23663540607603 |
9 | 4742082633444 |
10 | 1364147244931 |
11 | 4865936137a9 |
12 | 1a046a19b057 |
13 | 9b83bb1bbc3 |
14 | 4a04cb60b19 |
15 | 257407d6421 |
hex | 13d9d830f83 |
1364147244931 has 2 divisors, whose sum is σ = 1364147244932. Its totient is φ = 1364147244930.
The previous prime is 1364147244907. The next prime is 1364147244937. The reversal of 1364147244931 is 1394427414631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1364147244931 - 217 = 1364147113859 is a prime.
It is a super-2 number, since 2×13641472449312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1364147244937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 682073622465 + 682073622466.
It is an arithmetic number, because the mean of its divisors is an integer number (682073622466).
Almost surely, 21364147244931 is an apocalyptic number.
1364147244931 is a deficient number, since it is larger than the sum of its proper divisors (1).
1364147244931 is an equidigital number, since it uses as much as digits as its factorization.
1364147244931 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1741824, while the sum is 49.
The spelling of 1364147244931 in words is "one trillion, three hundred sixty-four billion, one hundred forty-seven million, two hundred forty-four thousand, nine hundred thirty-one".
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