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136414954391 = 367371702873
BaseRepresentation
bin111111100001011110…
…1110000001110010111
3111001002222210200201012
41333002331300032113
54213334212020031
6142400153522435
712566326660202
oct1770275601627
9431088720635
10136414954391
115294275a331
122253111341b
13cb2cc19831
146861452939
153836115b2b
hex1fc2f70397

136414954391 has 4 divisors (see below), whose sum is σ = 136786657632. Its totient is φ = 136043251152.

The previous prime is 136414954367. The next prime is 136414954393. The reversal of 136414954391 is 193459414631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136414954391 is a prime.

It is a super-2 number, since 2×1364149543912 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (136414954393) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185851070 + ... + 185851803.

It is an arithmetic number, because the mean of its divisors is an integer number (34196664408).

Almost surely, 2136414954391 is an apocalyptic number.

136414954391 is a deficient number, since it is larger than the sum of its proper divisors (371703241).

136414954391 is an equidigital number, since it uses as much as digits as its factorization.

136414954391 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 371703240.

The product of its digits is 1399680, while the sum is 50.

The spelling of 136414954391 in words is "one hundred thirty-six billion, four hundred fourteen million, nine hundred fifty-four thousand, three hundred ninety-one".

Divisors: 1 367 371702873 136414954391