136414954393 has 2 divisors, whose sum is σ = 136414954394. Its totient is φ = 136414954392.

The previous prime is 136414954367. The next prime is 136414954409. The reversal of 136414954393 is 393459414631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68334142464 + 68080811929 = 261408^2 + 260923^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-136414954393 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 136414954393.

It is not a weakly prime, because it can be changed into another prime (136414934393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68207477196 + 68207477197.

It is an arithmetic number, because the mean of its divisors is an integer number (68207477197).

Almost surely, 2^136414954393 is an apocalyptic number.

It is an amenable number.

136414954393 is a deficient number, since it is larger than the sum of its proper divisors (1).

136414954393 is an equidigital number, since it uses as much as digits as its factorization.

136414954393 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4199040, while the sum is 52.

The spelling of 136414954393 in words is "one hundred thirty-six billion, four hundred fourteen million, nine hundred fifty-four thousand, three hundred ninety-three".