1364204041103 has 4 divisors (see below), whose sum is σ = 1365052956240. Its totient is φ = 1363355125968.

The previous prime is 1364204041073. The next prime is 1364204041127. The reversal of 1364204041103 is 3011404024631.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1364204041103 - 2¹⁰ = 1364204040079 is a prime.

It is a super-2 number, since 2×1364204041103² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1364204041133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 424455158 + ... + 424458371.

It is an arithmetic number, because the mean of its divisors is an integer number (341263239060).

Almost surely, 2^{1364204041103} is an apocalyptic number.

1364204041103 is a deficient number, since it is larger than the sum of its proper divisors (848915137).

1364204041103 is an equidigital number, since it uses as much as digits as its factorization.

1364204041103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 848915136.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1364204041103 its reverse (3011404024631), we get a palindrome (4375608065734).

The spelling of 1364204041103 in words is "one trillion, three hundred sixty-four billion, two hundred four million, forty-one thousand, one hundred three".