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1364215406543 = 11532339992121
BaseRepresentation
bin10011110110100001100…
…100110001111111001111
311211102021111222002122122
4103312201210301333033
5134322403121002133
62522413434403155
7200363346425153
oct23664144617717
94742244862578
101364215406543
11486619039610
121a0488b904bb
139b84cc95a12
144a057c25063
152574679c498
hex13da1931fcf

1364215406543 has 8 divisors (see below), whose sum is σ = 1516314895056. Its totient is φ = 1216795902400.

The previous prime is 1364215406539. The next prime is 1364215406557. The reversal of 1364215406543 is 3456045124631.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1364215406543 - 22 = 1364215406539 is a prime.

It is a super-2 number, since 2×13642154065432 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1364215406494 and 1364215406503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1364215406143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1169995478 + ... + 1169996643.

It is an arithmetic number, because the mean of its divisors is an integer number (189539361882).

Almost surely, 21364215406543 is an apocalyptic number.

1364215406543 is a deficient number, since it is larger than the sum of its proper divisors (152099488513).

1364215406543 is a wasteful number, since it uses less digits than its factorization.

1364215406543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2339992185.

The product of its (nonzero) digits is 1036800, while the sum is 44.

The spelling of 1364215406543 in words is "one trillion, three hundred sixty-four billion, two hundred fifteen million, four hundred six thousand, five hundred forty-three".

Divisors: 1 11 53 583 2339992121 25739913331 124019582413 1364215406543