Search a number
-
+
13642230053111 = 111240202732101
BaseRepresentation
bin1100011010000101010001…
…0001101011100011110111
31210022011222110122120000212
43012201110101223203313
53242003241343144421
645003053131300035
72605422115105652
oct306412421534367
953264873576025
1013642230053111
11438a701238230
121643b572aa61b
1377c5c26bca1a
14352404ad8899
15189cebb92e5b
hexc685446b8f7

13642230053111 has 4 divisors (see below), whose sum is σ = 14882432785224. Its totient is φ = 12402027321000.

The previous prime is 13642230053071. The next prime is 13642230053149. The reversal of 13642230053111 is 11135003224631.

13642230053111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13642230053111 is a prime.

It is a super-2 number, since 2×136422300531112 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13642230053611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 620101366040 + ... + 620101366061.

It is an arithmetic number, because the mean of its divisors is an integer number (3720608196306).

Almost surely, 213642230053111 is an apocalyptic number.

13642230053111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13642230053111 is a deficient number, since it is larger than the sum of its proper divisors (1240202732113).

13642230053111 is a wasteful number, since it uses less digits than its factorization.

13642230053111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1240202732112.

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 13642230053111 its reverse (11135003224631), we get a palindrome (24777233277742).

The spelling of 13642230053111 in words is "thirteen trillion, six hundred forty-two billion, two hundred thirty million, fifty-three thousand, one hundred eleven".

Divisors: 1 11 1240202732101 13642230053111