Base | Representation |
---|---|
bin | 1100011010000101010001… |
… | …0001101011100011110111 |
3 | 1210022011222110122120000212 |
4 | 3012201110101223203313 |
5 | 3242003241343144421 |
6 | 45003053131300035 |
7 | 2605422115105652 |
oct | 306412421534367 |
9 | 53264873576025 |
10 | 13642230053111 |
11 | 438a701238230 |
12 | 1643b572aa61b |
13 | 77c5c26bca1a |
14 | 352404ad8899 |
15 | 189cebb92e5b |
hex | c685446b8f7 |
13642230053111 has 4 divisors (see below), whose sum is σ = 14882432785224. Its totient is φ = 12402027321000.
The previous prime is 13642230053071. The next prime is 13642230053149. The reversal of 13642230053111 is 11135003224631.
13642230053111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13642230053111 is a prime.
It is a super-2 number, since 2×136422300531112 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13642230053611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 620101366040 + ... + 620101366061.
It is an arithmetic number, because the mean of its divisors is an integer number (3720608196306).
Almost surely, 213642230053111 is an apocalyptic number.
13642230053111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13642230053111 is a deficient number, since it is larger than the sum of its proper divisors (1240202732113).
13642230053111 is a wasteful number, since it uses less digits than its factorization.
13642230053111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1240202732112.
The product of its (nonzero) digits is 12960, while the sum is 32.
Adding to 13642230053111 its reverse (11135003224631), we get a palindrome (24777233277742).
The spelling of 13642230053111 in words is "thirteen trillion, six hundred forty-two billion, two hundred thirty million, fifty-three thousand, one hundred eleven".
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