Base | Representation |
---|---|
bin | 1100011010000101100011… |
… | …0001010001001000011011 |
3 | 1210022012011201111201121012 |
4 | 3012201120301101020123 |
5 | 3242003420143123311 |
6 | 45003104423204135 |
7 | 2605424021646416 |
oct | 306413061211033 |
9 | 53265151451535 |
10 | 13642305442331 |
11 | 438a73a84a275 |
12 | 1643b785a664b |
13 | 77c6051c7527 |
14 | 352410b20b7d |
15 | 189d035d578b |
hex | c6858c5121b |
13642305442331 has 16 divisors (see below), whose sum is σ = 13798577469600. Its totient is φ = 13486896783360.
The previous prime is 13642305442279. The next prime is 13642305442333. The reversal of 13642305442331 is 13324450324631.
It is not a de Polignac number, because 13642305442331 - 222 = 13642301248027 is a prime.
It is a super-2 number, since 2×136423054423312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13642305442333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48368291 + ... + 48649523.
It is an arithmetic number, because the mean of its divisors is an integer number (862411091850).
Almost surely, 213642305442331 is an apocalyptic number.
13642305442331 is a deficient number, since it is larger than the sum of its proper divisors (156272027269).
13642305442331 is a wasteful number, since it uses less digits than its factorization.
13642305442331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 282766.
The product of its (nonzero) digits is 622080, while the sum is 41.
Adding to 13642305442331 its reverse (13324450324631), we get a palindrome (26966755766962).
The spelling of 13642305442331 in words is "thirteen trillion, six hundred forty-two billion, three hundred five million, four hundred forty-two thousand, three hundred thirty-one".
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