Base | Representation |
---|---|
bin | 11111000001001110001101… |
… | …101110110010011110100011 |
3 | 122220000221200222122112201111 |
4 | 133001032031232302132203 |
5 | 120340130133030410213 |
6 | 1202052020020244151 |
7 | 40510160424400543 |
oct | 3701161556623643 |
9 | 586027628575644 |
10 | 136423424075683 |
11 | 3a517938380808 |
12 | 13373934840657 |
13 | 5b1789b133314 |
14 | 2598d010ad323 |
15 | 10b8a465a6a3d |
hex | 7c138dbb27a3 |
136423424075683 has 2 divisors, whose sum is σ = 136423424075684. Its totient is φ = 136423424075682.
The previous prime is 136423424075647. The next prime is 136423424075711. The reversal of 136423424075683 is 386570424324631.
It is a strong prime.
It is an emirp because it is prime and its reverse (386570424324631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 136423424075683 - 229 = 136422887204771 is a prime.
It is a super-2 number, since 2×1364234240756832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (136423424075623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68211712037841 + 68211712037842.
It is an arithmetic number, because the mean of its divisors is an integer number (68211712037842).
Almost surely, 2136423424075683 is an apocalyptic number.
136423424075683 is a deficient number, since it is larger than the sum of its proper divisors (1).
136423424075683 is an equidigital number, since it uses as much as digits as its factorization.
136423424075683 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69672960, while the sum is 58.
The spelling of 136423424075683 in words is "one hundred thirty-six trillion, four hundred twenty-three billion, four hundred twenty-four million, seventy-five thousand, six hundred eighty-three".
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