Base | Representation |
---|---|
bin | 10011110110100110110… |
… | …010111011001101100111 |
3 | 11211102111121210022212102 |
4 | 103312212302323031213 |
5 | 134323043032003143 |
6 | 2522430244042315 |
7 | 200365462106666 |
oct | 23664662731547 |
9 | 4742447708772 |
10 | 1364303000423 |
11 | 486663527150 |
12 | 1a04b239339b |
13 | 9b86518470c |
14 | 4a065706ddd |
15 | 2574e3010b8 |
hex | 13da6cbb367 |
1364303000423 has 4 divisors (see below), whose sum is σ = 1488330545928. Its totient is φ = 1240275454920.
The previous prime is 1364303000323. The next prime is 1364303000447. The reversal of 1364303000423 is 3240003034631.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1364303000423 - 28 = 1364303000167 is a prime.
It is a super-2 number, since 2×13643030004232 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1364303000453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62013772736 + ... + 62013772757.
It is an arithmetic number, because the mean of its divisors is an integer number (372082636482).
Almost surely, 21364303000423 is an apocalyptic number.
1364303000423 is a deficient number, since it is larger than the sum of its proper divisors (124027545505).
1364303000423 is a wasteful number, since it uses less digits than its factorization.
1364303000423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 124027545504.
The product of its (nonzero) digits is 15552, while the sum is 29.
The spelling of 1364303000423 in words is "one trillion, three hundred sixty-four billion, three hundred three million, four hundred twenty-three", and thus it is an aban number.
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