Base | Representation |
---|---|
bin | 10011110110101101001… |
… | …101000101011000010011 |
3 | 11211102210010002221111222 |
4 | 103312231031011120103 |
5 | 134323303043133412 |
6 | 2522445044355255 |
7 | 200401236034244 |
oct | 23665515053023 |
9 | 4742703087458 |
10 | 1364410521107 |
11 | 486709195017 |
12 | 1a05223a5b2b |
13 | 9b88152c41a |
14 | 4a075ad4ccb |
15 | 2575898e072 |
hex | 13dad345613 |
1364410521107 has 2 divisors, whose sum is σ = 1364410521108. Its totient is φ = 1364410521106.
The previous prime is 1364410521043. The next prime is 1364410521119. The reversal of 1364410521107 is 7011250144631.
It is a strong prime.
It is an emirp because it is prime and its reverse (7011250144631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1364410521107 - 26 = 1364410521043 is a prime.
It is not a weakly prime, because it can be changed into another prime (1364410521407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 682205260553 + 682205260554.
It is an arithmetic number, because the mean of its divisors is an integer number (682205260554).
Almost surely, 21364410521107 is an apocalyptic number.
1364410521107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1364410521107 is an equidigital number, since it uses as much as digits as its factorization.
1364410521107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 35.
Adding to 1364410521107 its reverse (7011250144631), we get a palindrome (8375660665738).
The spelling of 1364410521107 in words is "one trillion, three hundred sixty-four billion, four hundred ten million, five hundred twenty-one thousand, one hundred seven".
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