Base | Representation |
---|---|
bin | 1100011010001101110110… |
… | …1100000101010111000011 |
3 | 1210022101221010200000022111 |
4 | 3012203131230011113003 |
5 | 3242023002033444443 |
6 | 45004114004120151 |
7 | 2605533210510541 |
oct | 306433554052703 |
9 | 53271833600274 |
10 | 13644535453123 |
11 | 43906846073a3 |
12 | 164449b396057 |
13 | 77c89c205a43 |
14 | 352582d70d91 |
15 | 189dd427e69d |
hex | c68ddb055c3 |
13644535453123 has 2 divisors, whose sum is σ = 13644535453124. Its totient is φ = 13644535453122.
The previous prime is 13644535453111. The next prime is 13644535453229. The reversal of 13644535453123 is 32135453544631.
13644535453123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13644535453123 - 217 = 13644535322051 is a prime.
It is not a weakly prime, because it can be changed into another prime (13644533453123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6822267726561 + 6822267726562.
It is an arithmetic number, because the mean of its divisors is an integer number (6822267726562).
Almost surely, 213644535453123 is an apocalyptic number.
13644535453123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13644535453123 is an equidigital number, since it uses as much as digits as its factorization.
13644535453123 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7776000, while the sum is 49.
Adding to 13644535453123 its reverse (32135453544631), we get a palindrome (45779988997754).
The spelling of 13644535453123 in words is "thirteen trillion, six hundred forty-four billion, five hundred thirty-five million, four hundred fifty-three thousand, one hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.090 sec. • engine limits •