Base | Representation |
---|---|
bin | 11001011010111111… |
… | …10011101101000101 |
3 | 1022020011112011002000 |
4 | 30231133303231011 |
5 | 210422420333403 |
6 | 10134144335513 |
7 | 662133624600 |
oct | 145537635505 |
9 | 38204464060 |
10 | 13648214853 |
11 | 5874074909 |
12 | 278a914599 |
13 | 139677c2a0 |
14 | 9368a3337 |
15 | 54d2e57a3 |
hex | 32d7f3b45 |
13648214853 has 48 divisors (see below), whose sum is σ = 25330052160. Its totient is φ = 7199049312.
The previous prime is 13648214851. The next prime is 13648214863. The reversal of 13648214853 is 35841284631.
It is not a de Polignac number, because 13648214853 - 21 = 13648214851 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13648214799 and 13648214808.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13648214851) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 379575 + ... + 413972.
It is an arithmetic number, because the mean of its divisors is an integer number (527709420).
Almost surely, 213648214853 is an apocalyptic number.
13648214853 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13648214853 is a deficient number, since it is larger than the sum of its proper divisors (11681837307).
13648214853 is a wasteful number, since it uses less digits than its factorization.
13648214853 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 793583 (or 793570 counting only the distinct ones).
The product of its digits is 552960, while the sum is 45.
The spelling of 13648214853 in words is "thirteen billion, six hundred forty-eight million, two hundred fourteen thousand, eight hundred fifty-three".
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