Base | Representation |
---|---|
bin | 11001011011000000… |
… | …10011100011111011 |
3 | 1022020011202210001211 |
4 | 30231200103203323 |
5 | 210422434022324 |
6 | 10134151223551 |
7 | 662135010166 |
oct | 145540234373 |
9 | 38204683054 |
10 | 13648345339 |
11 | 5874153952 |
12 | 278a977bb7 |
13 | 13967c67b5 |
14 | 9368d8add |
15 | 54d31e294 |
hex | 32d8138fb |
13648345339 has 2 divisors, whose sum is σ = 13648345340. Its totient is φ = 13648345338.
The previous prime is 13648345309. The next prime is 13648345367. The reversal of 13648345339 is 93354384631.
It is a strong prime.
It is an emirp because it is prime and its reverse (93354384631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13648345339 - 25 = 13648345307 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13648345292 and 13648345301.
It is not a weakly prime, because it can be changed into another prime (13648345309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6824172669 + 6824172670.
It is an arithmetic number, because the mean of its divisors is an integer number (6824172670).
Almost surely, 213648345339 is an apocalyptic number.
13648345339 is a deficient number, since it is larger than the sum of its proper divisors (1).
13648345339 is an equidigital number, since it uses as much as digits as its factorization.
13648345339 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2799360, while the sum is 49.
The spelling of 13648345339 in words is "thirteen billion, six hundred forty-eight million, three hundred forty-five thousand, three hundred thirty-nine".
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