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136511051 is a prime number
BaseRepresentation
bin10000010001011…
…11111001001011
3100111212110221212
420020233321023
5234421323201
621313523335
73245216255
oct1010577113
9314773855
10136511051
1170069856
123987354b
1322388291
14141b6cd5
15beb7abb
hex822fe4b

136511051 has 2 divisors, whose sum is σ = 136511052. Its totient is φ = 136511050.

The previous prime is 136511041. The next prime is 136511069. The reversal of 136511051 is 150115631.

136511051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (150115631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 136511051 - 214 = 136494667 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (136511021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68255525 + 68255526.

It is an arithmetic number, because the mean of its divisors is an integer number (68255526).

Almost surely, 2136511051 is an apocalyptic number.

136511051 is a deficient number, since it is larger than the sum of its proper divisors (1).

136511051 is an equidigital number, since it uses as much as digits as its factorization.

136511051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 450, while the sum is 23.

The square root of 136511051 is about 11683.7943751163. The cubic root of 136511051 is about 514.8996580830.

Adding to 136511051 its reverse (150115631), we get a palindrome (286626682).

The spelling of 136511051 in words is "one hundred thirty-six million, five hundred eleven thousand, fifty-one".