136513019 has 2 divisors, whose sum is σ = 136513020. Its totient is φ = 136513018.

The previous prime is 136512997. The next prime is 136513031. The reversal of 136513019 is 910315631.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 136513019 - 2¹² = 136508923 is a prime.

It is a super-2 number, since 2×136513019² = 37271608712988722, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 136512982 and 136513000.

It is not a weakly prime, because it can be changed into another prime (136513099) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68256509 + 68256510.

It is an arithmetic number, because the mean of its divisors is an integer number (68256510).

Almost surely, 2^136513019 is an apocalyptic number.

136513019 is a deficient number, since it is larger than the sum of its proper divisors (1).

136513019 is an equidigital number, since it uses as much as digits as its factorization.

136513019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2430, while the sum is 29.

The square root of 136513019 is about 11683.8785940286. The cubic root of 136513019 is about 514.9021324069.

The spelling of 136513019 in words is "one hundred thirty-six million, five hundred thirteen thousand, nineteen".