Base | Representation |
---|---|
bin | 10011110111011110011… |
… | …000001010111101111001 |
3 | 11211111220121110210010011 |
4 | 103313132120022331321 |
5 | 134332000242324121 |
6 | 2523102555021521 |
7 | 200430544242124 |
oct | 23673630127571 |
9 | 4744817423104 |
10 | 1365235511161 |
11 | 486aa1944285 |
12 | 1a071273a8a1 |
13 | 9b983421b12 |
14 | 4a1134c73bb |
15 | 257a61007e1 |
hex | 13dde60af79 |
1365235511161 has 2 divisors, whose sum is σ = 1365235511162. Its totient is φ = 1365235511160.
The previous prime is 1365235511099. The next prime is 1365235511173. The reversal of 1365235511161 is 1611155325631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 849899610000 + 515335901161 = 921900^2 + 717869^2 .
It is an emirp because it is prime and its reverse (1611155325631) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1365235511161 is a prime.
It is not a weakly prime, because it can be changed into another prime (1365235514161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 682617755580 + 682617755581.
It is an arithmetic number, because the mean of its divisors is an integer number (682617755581).
Almost surely, 21365235511161 is an apocalyptic number.
It is an amenable number.
1365235511161 is a deficient number, since it is larger than the sum of its proper divisors (1).
1365235511161 is an equidigital number, since it uses as much as digits as its factorization.
1365235511161 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 81000, while the sum is 40.
The spelling of 1365235511161 in words is "one trillion, three hundred sixty-five billion, two hundred thirty-five million, five hundred eleven thousand, one hundred sixty-one".
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