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13653050299241 is a prime number
BaseRepresentation
bin1100011010101101100100…
…1101101001001101101001
31210100012220112212000022112
43012223121031221031221
53242142421334033431
645012042534532105
72606254212510023
oct306533115511551
953305815760275
1013653050299241
114394253a61301
121646076b07035
137806282cb522
14352b4db77013
1518a231a76c2b
hexc6ad9369369

13653050299241 has 2 divisors, whose sum is σ = 13653050299242. Its totient is φ = 13653050299240.

The previous prime is 13653050299181. The next prime is 13653050299267. The reversal of 13653050299241 is 14299205035631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8454632059225 + 5198418240016 = 2907685^2 + 2280004^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13653050299241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13653050299241.

It is not a weakly prime, because it can be changed into another prime (13653050293241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6826525149620 + 6826525149621.

It is an arithmetic number, because the mean of its divisors is an integer number (6826525149621).

Almost surely, 213653050299241 is an apocalyptic number.

It is an amenable number.

13653050299241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13653050299241 is an equidigital number, since it uses as much as digits as its factorization.

13653050299241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1749600, while the sum is 50.

The spelling of 13653050299241 in words is "thirteen trillion, six hundred fifty-three billion, fifty million, two hundred ninety-nine thousand, two hundred forty-one".