Base | Representation |
---|---|
bin | 111111100101100000… |
… | …1001000100100001011 |
3 | 111001110102000200100212 |
4 | 1333023001020210023 |
5 | 4214123303331001 |
6 | 142421421351335 |
7 | 12602560226045 |
oct | 1771301104413 |
9 | 431412020325 |
10 | 136550058251 |
11 | 52a01a47912 |
12 | 2256a40854b |
13 | cb51c01449 |
14 | 6875380a95 |
15 | 3842e017bb |
hex | 1fcb04890b |
136550058251 has 2 divisors, whose sum is σ = 136550058252. Its totient is φ = 136550058250.
The previous prime is 136550058233. The next prime is 136550058299. The reversal of 136550058251 is 152850055631.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136550058251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 136550058199 and 136550058208.
It is not a weakly prime, because it can be changed into another prime (136550055251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68275029125 + 68275029126.
It is an arithmetic number, because the mean of its divisors is an integer number (68275029126).
Almost surely, 2136550058251 is an apocalyptic number.
136550058251 is a deficient number, since it is larger than the sum of its proper divisors (1).
136550058251 is an equidigital number, since it uses as much as digits as its factorization.
136550058251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 180000, while the sum is 41.
The spelling of 136550058251 in words is "one hundred thirty-six billion, five hundred fifty million, fifty-eight thousand, two hundred fifty-one".
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