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136550074657 is a prime number
BaseRepresentation
bin111111100101100000…
…1001100100100100001
3111001110102001111212111
41333023001030210201
54214123304342112
6142421421555321
712602560324633
oct1771301144441
9431412044774
10136550074657
1152a01a59177
122256a415b41
13cb51c08a59
146875386a53
153842e065a7
hex1fcb04c921

136550074657 has 2 divisors, whose sum is σ = 136550074658. Its totient is φ = 136550074656.

The previous prime is 136550074651. The next prime is 136550074669. The reversal of 136550074657 is 756470055631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130887662656 + 5662412001 = 361784^2 + 75249^2 .

It is a cyclic number.

It is not a de Polignac number, because 136550074657 - 23 = 136550074649 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 136550074657.

It is not a weakly prime, because it can be changed into another prime (136550074651) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68275037328 + 68275037329.

It is an arithmetic number, because the mean of its divisors is an integer number (68275037329).

Almost surely, 2136550074657 is an apocalyptic number.

It is an amenable number.

136550074657 is a deficient number, since it is larger than the sum of its proper divisors (1).

136550074657 is an equidigital number, since it uses as much as digits as its factorization.

136550074657 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2646000, while the sum is 49.

The spelling of 136550074657 in words is "one hundred thirty-six billion, five hundred fifty million, seventy-four thousand, six hundred fifty-seven".