Search a number
-
+
13655010041353 is a prime number
BaseRepresentation
bin1100011010110100111000…
…0001011101111000001001
31210100101222010110020002201
43012231032001131320021
53242210430032310403
645013005223000201
72606353610160622
oct306551601357011
953311863406081
1013655010041353
11439506a20158a
121646523299061
1378087b31b845
14352c98152a49
1518a2e8b3621d
hexc6b4e05de09

13655010041353 has 2 divisors, whose sum is σ = 13655010041354. Its totient is φ = 13655010041352.

The previous prime is 13655010041221. The next prime is 13655010041377. The reversal of 13655010041353 is 35314001055631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12417469488649 + 1237540552704 = 3523843^2 + 1112448^2 .

It is a cyclic number.

It is not a de Polignac number, because 13655010041353 - 241 = 11455986785801 is a prime.

It is not a weakly prime, because it can be changed into another prime (13655010041383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6827505020676 + 6827505020677.

It is an arithmetic number, because the mean of its divisors is an integer number (6827505020677).

Almost surely, 213655010041353 is an apocalyptic number.

It is an amenable number.

13655010041353 is a deficient number, since it is larger than the sum of its proper divisors (1).

13655010041353 is an equidigital number, since it uses as much as digits as its factorization.

13655010041353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81000, while the sum is 37.

Adding to 13655010041353 its reverse (35314001055631), we get a palindrome (48969011096984).

The spelling of 13655010041353 in words is "thirteen trillion, six hundred fifty-five billion, ten million, forty-one thousand, three hundred fifty-three".