Base | Representation |
---|---|
bin | 1100011010110100111000… |
… | …0001011101111000001001 |
3 | 1210100101222010110020002201 |
4 | 3012231032001131320021 |
5 | 3242210430032310403 |
6 | 45013005223000201 |
7 | 2606353610160622 |
oct | 306551601357011 |
9 | 53311863406081 |
10 | 13655010041353 |
11 | 439506a20158a |
12 | 1646523299061 |
13 | 78087b31b845 |
14 | 352c98152a49 |
15 | 18a2e8b3621d |
hex | c6b4e05de09 |
13655010041353 has 2 divisors, whose sum is σ = 13655010041354. Its totient is φ = 13655010041352.
The previous prime is 13655010041221. The next prime is 13655010041377. The reversal of 13655010041353 is 35314001055631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12417469488649 + 1237540552704 = 3523843^2 + 1112448^2 .
It is a cyclic number.
It is not a de Polignac number, because 13655010041353 - 241 = 11455986785801 is a prime.
It is not a weakly prime, because it can be changed into another prime (13655010041383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6827505020676 + 6827505020677.
It is an arithmetic number, because the mean of its divisors is an integer number (6827505020677).
Almost surely, 213655010041353 is an apocalyptic number.
It is an amenable number.
13655010041353 is a deficient number, since it is larger than the sum of its proper divisors (1).
13655010041353 is an equidigital number, since it uses as much as digits as its factorization.
13655010041353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81000, while the sum is 37.
Adding to 13655010041353 its reverse (35314001055631), we get a palindrome (48969011096984).
The spelling of 13655010041353 in words is "thirteen trillion, six hundred fifty-five billion, ten million, forty-one thousand, three hundred fifty-three".
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