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136553253737 is a prime number
BaseRepresentation
bin111111100101100110…
…1010100101101101001
3111001110122001000202012
41333023031110231221
54214130113104422
6142422014045305
712602626335245
oct1771315245551
9431418030665
10136553253737
1152a0382a70a
122256b4a9835
13cb5277ca74
146875973425
1538433334e2
hex1fcb354b69

136553253737 has 2 divisors, whose sum is σ = 136553253738. Its totient is φ = 136553253736.

The previous prime is 136553253689. The next prime is 136553253757. The reversal of 136553253737 is 737352355631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95372262976 + 41180990761 = 308824^2 + 202931^2 .

It is a cyclic number.

It is not a de Polignac number, because 136553253737 - 224 = 136536476521 is a prime.

It is a super-2 number, since 2×1365532537372 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (136553253757) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68276626868 + 68276626869.

It is an arithmetic number, because the mean of its divisors is an integer number (68276626869).

Almost surely, 2136553253737 is an apocalyptic number.

It is an amenable number.

136553253737 is a deficient number, since it is larger than the sum of its proper divisors (1).

136553253737 is an equidigital number, since it uses as much as digits as its factorization.

136553253737 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5953500, while the sum is 50.

The spelling of 136553253737 in words is "one hundred thirty-six billion, five hundred fifty-three million, two hundred fifty-three thousand, seven hundred thirty-seven".