Base | Representation |
---|---|
bin | 111111100101101000… |
… | …1101111110001010110 |
3 | 111001110201012221011010 |
4 | 1333023101233301112 |
5 | 4214130412210032 |
6 | 142422054553050 |
7 | 12602642234400 |
oct | 1771321576126 |
9 | 431421187133 |
10 | 136554413142 |
11 | 52a044517a4 |
12 | 2256b968786 |
13 | cb52a976c4 |
14 | 6875b95b70 |
15 | 38434b1ccc |
hex | 1fcb46fc56 |
136554413142 has 48 divisors (see below), whose sum is σ = 320509587312. Its totient is φ = 38670266880.
The previous prime is 136554413069. The next prime is 136554413159. The reversal of 136554413142 is 241314455631.
It is a self number, because there is not a number n which added to its sum of digits gives 136554413142.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2021959 + ... + 2088402.
It is an arithmetic number, because the mean of its divisors is an integer number (6677283069).
Almost surely, 2136554413142 is an apocalyptic number.
136554413142 is an abundant number, since it is smaller than the sum of its proper divisors (183955174170).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136554413142 is a wasteful number, since it uses less digits than its factorization.
136554413142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4110493 (or 4110486 counting only the distinct ones).
The product of its digits is 172800, while the sum is 39.
Adding to 136554413142 its reverse (241314455631), we get a palindrome (377868868773).
The spelling of 136554413142 in words is "one hundred thirty-six billion, five hundred fifty-four million, four hundred thirteen thousand, one hundred forty-two".
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