Base | Representation |
---|---|
bin | 10011110111110101111… |
… | …111010000101011000001 |
3 | 11211112221012211220122121 |
4 | 103313311333100223001 |
5 | 134333303144242423 |
6 | 2523210145204241 |
7 | 200443424235415 |
oct | 23676577205301 |
9 | 4745835756577 |
10 | 1365631634113 |
11 | 48718550131a |
12 | 1a0803330681 |
13 | 9ba175067b6 |
14 | 4a14dd5cd45 |
15 | 257cac9a45d |
hex | 13df5fd0ac1 |
1365631634113 has 2 divisors, whose sum is σ = 1365631634114. Its totient is φ = 1365631634112.
The previous prime is 1365631634063. The next prime is 1365631634123. The reversal of 1365631634113 is 3114361365631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1023158549169 + 342473084944 = 1011513^2 + 585212^2 .
It is a cyclic number.
It is not a de Polignac number, because 1365631634113 - 29 = 1365631633601 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1365631634113.
It is not a weakly prime, because it can be changed into another prime (1365631634123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 682815817056 + 682815817057.
It is an arithmetic number, because the mean of its divisors is an integer number (682815817057).
Almost surely, 21365631634113 is an apocalyptic number.
It is an amenable number.
1365631634113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1365631634113 is an equidigital number, since it uses as much as digits as its factorization.
1365631634113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 349920, while the sum is 43.
Adding to 1365631634113 its reverse (3114361365631), we get a palindrome (4479992999744).
The spelling of 1365631634113 in words is "one trillion, three hundred sixty-five billion, six hundred thirty-one million, six hundred thirty-four thousand, one hundred thirteen".
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