Base | Representation |
---|---|
bin | 111111100101111100… |
… | …0010110111001010011 |
3 | 111001111102021011112211 |
4 | 1333023320112321103 |
5 | 4214141010103432 |
6 | 142423055532551 |
7 | 12603124251655 |
oct | 1771370267123 |
9 | 431442234484 |
10 | 136564534867 |
11 | 52a0a135362 |
12 | 2257322a157 |
13 | cb54bcc7a7 |
14 | 687726c6d5 |
15 | 3844310d47 |
hex | 1fcbe16e53 |
136564534867 has 2 divisors, whose sum is σ = 136564534868. Its totient is φ = 136564534866.
The previous prime is 136564534837. The next prime is 136564534877. The reversal of 136564534867 is 768435465631.
It is a strong prime.
It is an emirp because it is prime and its reverse (768435465631) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136564534867 is a prime.
It is a super-3 number, since 3×1365645348673 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (136564534817) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68282267433 + 68282267434.
It is an arithmetic number, because the mean of its divisors is an integer number (68282267434).
Almost surely, 2136564534867 is an apocalyptic number.
136564534867 is a deficient number, since it is larger than the sum of its proper divisors (1).
136564534867 is an equidigital number, since it uses as much as digits as its factorization.
136564534867 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 43545600, while the sum is 58.
The spelling of 136564534867 in words is "one hundred thirty-six billion, five hundred sixty-four million, five hundred thirty-four thousand, eight hundred sixty-seven".
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