Base | Representation |
---|---|
bin | 111111100110000000… |
… | …0000001100001000011 |
3 | 111001111120001021011212 |
4 | 1333030000001201003 |
5 | 4214142013410301 |
6 | 142423211000335 |
7 | 12603150321551 |
oct | 1771400014103 |
9 | 431446037155 |
10 | 136566544451 |
11 | 52a10288177 |
12 | 22573a390ab |
13 | cb554543ac |
14 | 6877632bd1 |
15 | 38445ab4bb |
hex | 1fcc001843 |
136566544451 has 2 divisors, whose sum is σ = 136566544452. Its totient is φ = 136566544450.
The previous prime is 136566544421. The next prime is 136566544459. The reversal of 136566544451 is 154445665631.
It is a strong prime.
It is an emirp because it is prime and its reverse (154445665631) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136566544451 is a prime.
It is a super-3 number, since 3×1365665444513 (a number of 34 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 136566544451.
It is not a weakly prime, because it can be changed into another prime (136566544459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68283272225 + 68283272226.
It is an arithmetic number, because the mean of its divisors is an integer number (68283272226).
Almost surely, 2136566544451 is an apocalyptic number.
136566544451 is a deficient number, since it is larger than the sum of its proper divisors (1).
136566544451 is an equidigital number, since it uses as much as digits as its factorization.
136566544451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184000, while the sum is 50.
The spelling of 136566544451 in words is "one hundred thirty-six billion, five hundred sixty-six million, five hundred forty-four thousand, four hundred fifty-one".
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