Base | Representation |
---|---|
bin | 111111100110001101… |
… | …1010111000001110011 |
3 | 111001112001112100002021 |
4 | 1333030123113001303 |
5 | 4214200332213301 |
6 | 142424024332311 |
7 | 12603265245643 |
oct | 1771433270163 |
9 | 431461470067 |
10 | 136573710451 |
11 | 52a14332092 |
12 | 22576314097 |
13 | cb56a93029 |
14 | 687857a523 |
15 | 38450248a1 |
hex | 1fcc6d7073 |
136573710451 has 2 divisors, whose sum is σ = 136573710452. Its totient is φ = 136573710450.
The previous prime is 136573710397. The next prime is 136573710461. The reversal of 136573710451 is 154017375631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136573710451 - 215 = 136573677683 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 136573710398 and 136573710407.
It is not a weakly prime, because it can be changed into another prime (136573710461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68286855225 + 68286855226.
It is an arithmetic number, because the mean of its divisors is an integer number (68286855226).
Almost surely, 2136573710451 is an apocalyptic number.
136573710451 is a deficient number, since it is larger than the sum of its proper divisors (1).
136573710451 is an equidigital number, since it uses as much as digits as its factorization.
136573710451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 264600, while the sum is 43.
The spelling of 136573710451 in words is "one hundred thirty-six billion, five hundred seventy-three million, seven hundred ten thousand, four hundred fifty-one".
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