Base | Representation |
---|---|
bin | 1100011011010101100001… |
… | …1010001100011100100011 |
3 | 1210101020120220211011011121 |
4 | 3012311120122030130203 |
5 | 3242331402200332212 |
6 | 45021015021553111 |
7 | 2610114030434125 |
oct | 306653032143443 |
9 | 53336526734147 |
10 | 13663774230307 |
11 | 4398857380453 |
12 | 164816a415797 |
13 | 781646c86876 |
14 | 35348a103215 |
15 | 18a65d282d07 |
hex | c6d5868c723 |
13663774230307 has 2 divisors, whose sum is σ = 13663774230308. Its totient is φ = 13663774230306.
The previous prime is 13663774230259. The next prime is 13663774230311. The reversal of 13663774230307 is 70303247736631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13663774230307 - 27 = 13663774230179 is a prime.
It is a super-3 number, since 3×136637742303073 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (13663774230317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6831887115153 + 6831887115154.
It is an arithmetic number, because the mean of its divisors is an integer number (6831887115154).
Almost surely, 213663774230307 is an apocalyptic number.
13663774230307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13663774230307 is an equidigital number, since it uses as much as digits as its factorization.
13663774230307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8001504, while the sum is 52.
The spelling of 13663774230307 in words is "thirteen trillion, six hundred sixty-three billion, seven hundred seventy-four million, two hundred thirty thousand, three hundred seven".
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