Base | Representation |
---|---|
bin | 11111000100011100110110… |
… | …101111101111000101101111 |
3 | 122220211011102010000000200202 |
4 | 133010130312233233011233 |
5 | 120402244040032134201 |
6 | 1202341552515544115 |
7 | 40532203664234234 |
oct | 3704346657570557 |
9 | 586734363000622 |
10 | 136645303005551 |
11 | 3a5a2a4723582a |
12 | 133aa9375bb03b |
13 | 5b3279b194432 |
14 | 25a594cc1778b |
15 | 10be6d06e1c6b |
hex | 7c4736bef16f |
136645303005551 has 4 divisors (see below), whose sum is σ = 137515655254152. Its totient is φ = 135774950756952.
The previous prime is 136645303005503. The next prime is 136645303005581. The reversal of 136645303005551 is 155500303546631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136645303005551 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 136645303005496 and 136645303005505.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (136645303005581) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435176124065 + ... + 435176124378.
It is an arithmetic number, because the mean of its divisors is an integer number (34378913813538).
Almost surely, 2136645303005551 is an apocalyptic number.
136645303005551 is a deficient number, since it is larger than the sum of its proper divisors (870352248601).
136645303005551 is an equidigital number, since it uses as much as digits as its factorization.
136645303005551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 870352248600.
The product of its (nonzero) digits is 2430000, while the sum is 47.
The spelling of 136645303005551 in words is "one hundred thirty-six trillion, six hundred forty-five billion, three hundred three million, five thousand, five hundred fifty-one".
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