Base | Representation |
---|---|
bin | 11111000100100010110011… |
… | …111100001100010010000111 |
3 | 122220211202220211001020002001 |
4 | 133010202303330030102013 |
5 | 120402400134241441101 |
6 | 1202344531255130131 |
7 | 40532521322142340 |
oct | 3704426374142207 |
9 | 586752824036061 |
10 | 136651698390151 |
11 | 3a5a572926994a |
12 | 133b0021373947 |
13 | 5b3327a146a89 |
14 | 25a5d983490c7 |
15 | 10be956dca901 |
hex | 7c48b3f0c487 |
136651698390151 has 8 divisors (see below), whose sum is σ = 158820375853440. Its totient is φ = 115144772493048.
The previous prime is 136651698390139. The next prime is 136651698390167. The reversal of 136651698390151 is 151093896156631.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 136651698390151 - 231 = 136649550906503 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (136651698390131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 165437891101 + ... + 165437891926.
It is an arithmetic number, because the mean of its divisors is an integer number (19852546981680).
Almost surely, 2136651698390151 is an apocalyptic number.
136651698390151 is a deficient number, since it is larger than the sum of its proper divisors (22168677463289).
136651698390151 is an equidigital number, since it uses as much as digits as its factorization.
136651698390151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 330875783093.
The product of its (nonzero) digits is 31492800, while the sum is 64.
The spelling of 136651698390151 in words is "one hundred thirty-six trillion, six hundred fifty-one billion, six hundred ninety-eight million, three hundred ninety thousand, one hundred fifty-one".
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