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136664038458457 is a prime number
BaseRepresentation
bin11111000100101110010011…
…011101110100010001011001
3122220212221202211001122102221
4133010232103131310101121
5120403100422321132312
61202354331553424041
740533436163040016
oct3704562335642131
9586787684048387
10136664038458457
113a5aa990981904
12133b24a5b6b021
135b34495898043
1425a68091aa70d
1510bee2a422207
hex7c4b93774459

136664038458457 has 2 divisors, whose sum is σ = 136664038458458. Its totient is φ = 136664038458456.

The previous prime is 136664038458449. The next prime is 136664038458463. The reversal of 136664038458457 is 754854830466631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84730165600201 + 51933872858256 = 9204899^2 + 7206516^2 .

It is a cyclic number.

It is not a de Polignac number, because 136664038458457 - 23 = 136664038458449 is a prime.

It is a super-2 number, since 2×1366640384584572 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (136664038455457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68332019229228 + 68332019229229.

It is an arithmetic number, because the mean of its divisors is an integer number (68332019229229).

Almost surely, 2136664038458457 is an apocalyptic number.

It is an amenable number.

136664038458457 is a deficient number, since it is larger than the sum of its proper divisors (1).

136664038458457 is an equidigital number, since it uses as much as digits as its factorization.

136664038458457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1393459200, while the sum is 70.

The spelling of 136664038458457 in words is "one hundred thirty-six trillion, six hundred sixty-four billion, thirty-eight million, four hundred fifty-eight thousand, four hundred fifty-seven".