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136677080344793 is a prime number
BaseRepresentation
bin11111000100111010011100…
…110100101010100011011001
3122220221012102201200010011012
4133010322130310222203121
5120403304130032013133
61202404330042343305
740534410315200162
oct3704723464524331
9586835381603135
10136677080344793
113a60547376606a
12133b4b257bab35
135b35793844051
1425a72c531a769
1510c0440399b48
hex7c4e9cd2a8d9

136677080344793 has 2 divisors, whose sum is σ = 136677080344794. Its totient is φ = 136677080344792.

The previous prime is 136677080344757. The next prime is 136677080344807. The reversal of 136677080344793 is 397443080776631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70805627793664 + 65871452551129 = 8414608^2 + 8116123^2 .

It is a cyclic number.

It is not a de Polignac number, because 136677080344793 - 230 = 136676006602969 is a prime.

It is not a weakly prime, because it can be changed into another prime (136677080344193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68338540172396 + 68338540172397.

It is an arithmetic number, because the mean of its divisors is an integer number (68338540172397).

Almost surely, 2136677080344793 is an apocalyptic number.

It is an amenable number.

136677080344793 is a deficient number, since it is larger than the sum of its proper divisors (1).

136677080344793 is an equidigital number, since it uses as much as digits as its factorization.

136677080344793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384072192, while the sum is 68.

The spelling of 136677080344793 in words is "one hundred thirty-six trillion, six hundred seventy-seven billion, eighty million, three hundred forty-four thousand, seven hundred ninety-three".