Base | Representation |
---|---|
bin | 1100011011111110001001… |
… | …0001100000100111101001 |
3 | 1210102021201202120120002101 |
4 | 3012333202101200213221 |
5 | 3243021214322102131 |
6 | 45030020541133401 |
7 | 2610651150611464 |
oct | 306774221404751 |
9 | 53367652516071 |
10 | 13674677144041 |
11 | 43a2441827961 |
12 | 164a2b185a261 |
13 | 782693a4aa04 |
14 | 353c021402db |
15 | 18aa9a545c61 |
hex | c6fe24609e9 |
13674677144041 has 2 divisors, whose sum is σ = 13674677144042. Its totient is φ = 13674677144040.
The previous prime is 13674677144033. The next prime is 13674677144087. The reversal of 13674677144041 is 14044177647631.
13674677144041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13164851155600 + 509825988441 = 3628340^2 + 714021^2 .
It is a cyclic number.
It is not a de Polignac number, because 13674677144041 - 23 = 13674677144033 is a prime.
It is not a weakly prime, because it can be changed into another prime (13674677144741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6837338572020 + 6837338572021.
It is an arithmetic number, because the mean of its divisors is an integer number (6837338572021).
Almost surely, 213674677144041 is an apocalyptic number.
It is an amenable number.
13674677144041 is a deficient number, since it is larger than the sum of its proper divisors (1).
13674677144041 is an equidigital number, since it uses as much as digits as its factorization.
13674677144041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9483264, while the sum is 55.
The spelling of 13674677144041 in words is "thirteen trillion, six hundred seventy-four billion, six hundred seventy-seven million, one hundred forty-four thousand, forty-one".
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