Base | Representation |
---|---|
bin | 11001011110001101… |
… | …10001000101000011 |
3 | 1022022001022101111112 |
4 | 30233012301011003 |
5 | 211001323024211 |
6 | 10140551033535 |
7 | 662612216063 |
oct | 145706610503 |
9 | 38261271445 |
10 | 13675204931 |
11 | 5888329963 |
12 | 279796b8ab |
13 | 139c23c24b |
14 | 93a2cb3a3 |
15 | 55087788b |
hex | 32f1b1143 |
13675204931 has 2 divisors, whose sum is σ = 13675204932. Its totient is φ = 13675204930.
The previous prime is 13675204927. The next prime is 13675204973. The reversal of 13675204931 is 13940257631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13675204931 - 22 = 13675204927 is a prime.
It is a super-3 number, since 3×136752049313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (13675204901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6837602465 + 6837602466.
It is an arithmetic number, because the mean of its divisors is an integer number (6837602466).
Almost surely, 213675204931 is an apocalyptic number.
13675204931 is a deficient number, since it is larger than the sum of its proper divisors (1).
13675204931 is an equidigital number, since it uses as much as digits as its factorization.
13675204931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 41.
The spelling of 13675204931 in words is "thirteen billion, six hundred seventy-five million, two hundred four thousand, nine hundred thirty-one".
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