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13677157801230 = 235711171277272737
BaseRepresentation
bin1100011100000111011000…
…1000011101110100001110
31210102112010122101000000120
43013001312020131310032
53243041304344114410
645031111034205410
72611066502056260
oct307016610356416
953375118330016
1013677157801230
1143a34a501a370
12164a884583866
1378299a966bc1
14353d99797b30
1518ab93200570
hexc707621dd0e

13677157801230 has 256 divisors, whose sum is σ = 43366336948224. Its totient is φ = 2672725524480.

The previous prime is 13677157801217. The next prime is 13677157801253. The reversal of 13677157801230 is 3210875177631.

It is a Harshad number since it is a multiple of its sum of digits (51).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 50011422 + ... + 50284158.

It is an arithmetic number, because the mean of its divisors is an integer number (169399753704).

Almost surely, 213677157801230 is an apocalyptic number.

13677157801230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 13677157801230, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21683168474112).

13677157801230 is an abundant number, since it is smaller than the sum of its proper divisors (29689179146994).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13677157801230 is a wasteful number, since it uses less digits than its factorization.

13677157801230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 274059.

The product of its (nonzero) digits is 1481760, while the sum is 51.

The spelling of 13677157801230 in words is "thirteen trillion, six hundred seventy-seven billion, one hundred fifty-seven million, eight hundred one thousand, two hundred thirty".