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13677536321 is a prime number
BaseRepresentation
bin11001011110011111…
…01010010001000001
31022022012200211120022
430233033222101001
5211002422130241
610141113023225
7662641066121
oct145717522101
938265624508
1013677536321
115889681529
1227986b4b15
13139c877477
1493a736c81
15550b8854b
hex32f3ea441

13677536321 has 2 divisors, whose sum is σ = 13677536322. Its totient is φ = 13677536320.

The previous prime is 13677536273. The next prime is 13677536351. The reversal of 13677536321 is 12363577631.

13677536321 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11443650625 + 2233885696 = 106975^2 + 47264^2 .

It is an emirp because it is prime and its reverse (12363577631) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13677536321 is a prime.

It is not a weakly prime, because it can be changed into another prime (13677536351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6838768160 + 6838768161.

It is an arithmetic number, because the mean of its divisors is an integer number (6838768161).

Almost surely, 213677536321 is an apocalyptic number.

It is an amenable number.

13677536321 is a deficient number, since it is larger than the sum of its proper divisors (1).

13677536321 is an equidigital number, since it uses as much as digits as its factorization.

13677536321 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 476280, while the sum is 44.

The spelling of 13677536321 in words is "thirteen billion, six hundred seventy-seven million, five hundred thirty-six thousand, three hundred twenty-one".