Base | Representation |
---|---|
bin | 1100011100010101010110… |
… | …1010100110101100010011 |
3 | 1210102212211000011101010222 |
4 | 3013011111222212230103 |
5 | 3243121444431212101 |
6 | 45032531123343255 |
7 | 2611261440606404 |
oct | 307052552465423 |
9 | 53385730141128 |
10 | 13680908069651 |
11 | 43a5049a43559 |
12 | 164b550521b2b |
13 | 78314790b144 |
14 | 3542338a19ab |
15 | 18ad1259601b |
hex | c7155aa6b13 |
13680908069651 has 2 divisors, whose sum is σ = 13680908069652. Its totient is φ = 13680908069650.
The previous prime is 13680908069639. The next prime is 13680908069657. The reversal of 13680908069651 is 15696080908631.
13680908069651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13680908069651 is a prime.
It is a super-2 number, since 2×136809080696512 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13680908069657) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6840454034825 + 6840454034826.
It is an arithmetic number, because the mean of its divisors is an integer number (6840454034826).
Almost surely, 213680908069651 is an apocalyptic number.
13680908069651 is a deficient number, since it is larger than the sum of its proper divisors (1).
13680908069651 is an equidigital number, since it uses as much as digits as its factorization.
13680908069651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16796160, while the sum is 62.
The spelling of 13680908069651 in words is "thirteen trillion, six hundred eighty billion, nine hundred eight million, sixty-nine thousand, six hundred fifty-one".
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