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136817113 is a prime number
BaseRepresentation
bin10000010011110…
…10100111011001
3100112110000210111
420021322213121
5240011121423
621324244321
73250632466
oct1011724731
9315400714
10136817113
11702587a4
12399a06a1
1322464694
141425666d
15c02860d
hex827a9d9

136817113 has 2 divisors, whose sum is σ = 136817114. Its totient is φ = 136817112.

The previous prime is 136817059. The next prime is 136817129. The reversal of 136817113 is 311718631.

136817113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114661264 + 22155849 = 10708^2 + 4707^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136817113 is a prime.

It is not a weakly prime, because it can be changed into another prime (136817183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68408556 + 68408557.

It is an arithmetic number, because the mean of its divisors is an integer number (68408557).

Almost surely, 2136817113 is an apocalyptic number.

It is an amenable number.

136817113 is a deficient number, since it is larger than the sum of its proper divisors (1).

136817113 is an equidigital number, since it uses as much as digits as its factorization.

136817113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3024, while the sum is 31.

The square root of 136817113 is about 11696.8847562075. The cubic root of 136817113 is about 515.2841778457.

It can be divided in two parts, 1368 and 17113, that added together give a palindrome (18481).

The spelling of 136817113 in words is "one hundred thirty-six million, eight hundred seventeen thousand, one hundred thirteen".