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13684781260817 is a prime number
BaseRepresentation
bin1100011100100011110010…
…0001101010000000010001
31210110020210221020212120122
43013020330201222000101
53243202413000321232
645034411323320025
72611456431313052
oct307107441520021
953406727225518
1013684781260817
1143a6757295397
121650251680015
13783614190734
143544c0046729
1518ae8c61d312
hexc723c86a011

13684781260817 has 2 divisors, whose sum is σ = 13684781260818. Its totient is φ = 13684781260816.

The previous prime is 13684781260763. The next prime is 13684781260837. The reversal of 13684781260817 is 71806218748631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9964477102336 + 3720304158481 = 3156656^2 + 1928809^2 .

It is a cyclic number.

It is not a de Polignac number, because 13684781260817 - 236 = 13616061784081 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13684781260817.

It is not a weakly prime, because it can be changed into another prime (13684781260837) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6842390630408 + 6842390630409.

It is an arithmetic number, because the mean of its divisors is an integer number (6842390630409).

Almost surely, 213684781260817 is an apocalyptic number.

It is an amenable number.

13684781260817 is a deficient number, since it is larger than the sum of its proper divisors (1).

13684781260817 is an equidigital number, since it uses as much as digits as its factorization.

13684781260817 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21676032, while the sum is 62.

The spelling of 13684781260817 in words is "thirteen trillion, six hundred eighty-four billion, seven hundred eighty-one million, two hundred sixty thousand, eight hundred seventeen".