Base | Representation |
---|---|
bin | 11001011111011010… |
… | …11000000111011101 |
3 | 1022022202100121102002 |
4 | 30233231120013131 |
5 | 211011420420201 |
6 | 10141552012045 |
7 | 663064232333 |
oct | 145755300735 |
9 | 38282317362 |
10 | 13685326301 |
11 | 5893012229 |
12 | 279b231025 |
13 | 13a137411a |
14 | 93b7a3b53 |
15 | 5516c676b |
hex | 32fb581dd |
13685326301 has 4 divisors (see below), whose sum is σ = 14280340512. Its totient is φ = 13090312092.
The previous prime is 13685326273. The next prime is 13685326307. The reversal of 13685326301 is 10362358631.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10362358631 = 1193 ⋅8685967.
It is a de Polignac number, because none of the positive numbers 2k-13685326301 is a prime.
It is a super-4 number, since 4×136853263014 (a number of 42 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13685326307) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 297507071 + ... + 297507116.
It is an arithmetic number, because the mean of its divisors is an integer number (3570085128).
Almost surely, 213685326301 is an apocalyptic number.
It is an amenable number.
13685326301 is a deficient number, since it is larger than the sum of its proper divisors (595014211).
13685326301 is an equidigital number, since it uses as much as digits as its factorization.
13685326301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 595014210.
The product of its (nonzero) digits is 77760, while the sum is 38.
The spelling of 13685326301 in words is "thirteen billion, six hundred eighty-five million, three hundred twenty-six thousand, three hundred one".
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