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13686471743401 is a prime number
BaseRepresentation
bin1100011100101010000101…
…0010010101011110101001
31210110102011202012021201201
43013022201102111132221
53243214343231242101
645035251152244201
72611546346215522
oct307124122253651
953412152167651
1013686471743401
1143a7444547a36
121650643840661
13783823486ca2
14354600771849
1518b03ac41e01
hexc72a14957a9

13686471743401 has 2 divisors, whose sum is σ = 13686471743402. Its totient is φ = 13686471743400.

The previous prime is 13686471743377. The next prime is 13686471743429. The reversal of 13686471743401 is 10434717468631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13091544914176 + 594926829225 = 3618224^2 + 771315^2 .

It is a cyclic number.

It is not a de Polignac number, because 13686471743401 - 215 = 13686471710633 is a prime.

It is not a weakly prime, because it can be changed into another prime (13686475743401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6843235871700 + 6843235871701.

It is an arithmetic number, because the mean of its divisors is an integer number (6843235871701).

Almost surely, 213686471743401 is an apocalyptic number.

It is an amenable number.

13686471743401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13686471743401 is an equidigital number, since it uses as much as digits as its factorization.

13686471743401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8128512, while the sum is 55.

The spelling of 13686471743401 in words is "thirteen trillion, six hundred eighty-six billion, four hundred seventy-one million, seven hundred forty-three thousand, four hundred one".